3[4x-4(y-2)]=

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Solution for 3[4x-4(y-2)]= equation:


Simplifying
3[4x + -4(y + -2)] = 0

Reorder the terms:
3[4x + -4(-2 + y)] = 0
3[4x + (-2 * -4 + y * -4)] = 0
3[4x + (8 + -4y)] = 0

Reorder the terms:
3[8 + 4x + -4y] = 0
[8 * 3 + 4x * 3 + -4y * 3] = 0
[24 + 12x + -12y] = 0

Solving
24 + 12x + -12y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-24' to each side of the equation.
24 + 12x + -24 + -12y = 0 + -24

Reorder the terms:
24 + -24 + 12x + -12y = 0 + -24

Combine like terms: 24 + -24 = 0
0 + 12x + -12y = 0 + -24
12x + -12y = 0 + -24

Combine like terms: 0 + -24 = -24
12x + -12y = -24

Add '12y' to each side of the equation.
12x + -12y + 12y = -24 + 12y

Combine like terms: -12y + 12y = 0
12x + 0 = -24 + 12y
12x = -24 + 12y

Divide each side by '12'.
x = -2 + y

Simplifying
x = -2 + y

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